x^2+9x+9=3+4x

Solution for x^2+9x+9=3+4x equation:

x^2+9x+9=3+4x

We move all terms to the left:

x^2+9x+9-(3+4x)=0

We add all the numbers together, and all the variables

x^2+9x-(4x+3)+9=0

We get rid of parentheses

x^2+9x-4x-3+9=0

We add all the numbers together, and all the variables

x^2+5x+6=0

a = 1; b = 5; c = +6;
Δ = b2-4ac
Δ = 52-4·1·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-1}{2*1}=\frac{-6}{2}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+1}{2*1}=\frac{-4}{2}
=-2
$